Find roots of polynomial $$ p(x) = 2r^2+3r+1 $$
Answer
The roots of polynomial $ p(r) $ are:
$$ \begin{aligned}r_1 &= -\frac{ 1 }{ 2 }\\[1 em]r_2 &= -1 \end{aligned} $$Explanation
The solutions of $ 2r^2+3r+1 = 0 $ are: $ r = -1 ~ \text{and} ~ r = -\dfrac{ 1 }{ 2 }$.
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