Find roots of polynomial $$ p(x) = 28p^2-33p-1 $$
Answer
The roots of polynomial $ p(p) $ are:
$$ \begin{aligned}p_1 &= 1.2081\\[1 em]p_2 &= -0.0296 \end{aligned} $$Explanation
The solutions of $ 28p^2-33p-1 = 0 $ are: $ p = \dfrac{ 33 }{ 56 }-\dfrac{\sqrt{ 1201 }}{ 56 } ~ \text{and} ~ p = \dfrac{ 33 }{ 56 }+\dfrac{\sqrt{ 1201 }}{ 56 }$.
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