Find roots of polynomial $$ p(x) = 25x^2+48x-673 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.3165\\[1 em]x_2 &= -6.2365 \end{aligned} $$Explanation
The solutions of $ 25x^2+48x-673 = 0 $ are: $ x = -\dfrac{ 24 }{ 25 }-\dfrac{\sqrt{ 17401 }}{ 25 } ~ \text{and} ~ x = -\dfrac{ 24 }{ 25 }+\dfrac{\sqrt{ 17401 }}{ 25 }$.
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