Find roots of polynomial $$ p(x) = 21x^2+64x+35 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -\frac{ 5 }{ 7 }\\[1 em]x_2 &= -\frac{ 7 }{ 3 } \end{aligned} $$Explanation
The solutions of $ 21x^2+64x+35 = 0 $ are: $ x = -\dfrac{ 7 }{ 3 } ~ \text{and} ~ x = -\dfrac{ 5 }{ 7 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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