Find roots of polynomial $$ p(x) = 21x^2+24x-52 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.1027\\[1 em]x_2 &= -2.2456 \end{aligned} $$Explanation
The solutions of $ 21x^2+24x-52 = 0 $ are: $ x = -\dfrac{ 4 }{ 7 }-\dfrac{ 2 \sqrt{ 309}}{ 21 } ~ \text{and} ~ x = -\dfrac{ 4 }{ 7 }+\dfrac{ 2 \sqrt{ 309}}{ 21 }$.
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