Find roots of polynomial $$ p(x) = 20x^4+29x^3-497x^2-932+960 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.2393\\[1 em]x_2 &= -0.236\\[1 em]x_3 &= 4.3049\\[1 em]x_4 &= -5.7582 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ 20x^4+29x^3-497x^2 \color{blue}{-932} + \color{blue}{960} = 20x^4+29x^3-497x^2+ \color{blue}{28} $$Step 2:
Polynomial $ 20x^4+29x^3-497x^2+28 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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