Find roots of polynomial $$ p(x) = 2000-1000x+45x $$

The root of polynomial $ p(x) $ is:

$$ \begin{aligned}x &= \frac{ 400 }{ 191 } \end{aligned} $$

Step 1:

Combine like terms:

$$ 2000 \color{blue}{-1000x} + \color{blue}{45x} = \color{blue}{-955x} +2000 $$

Step 2:

$$ \begin{aligned} -955x+2000 & = 0 \\[1 em] -955 \cdot x & = -2000 \\[1 em] x & = - \frac{ 2000 }{ -955 } \\[1 em] x & = - \frac{ 2000 : 5 }{ -955 : 5} \\[1 em] x & = \frac{ 400 }{ 191 } \end{aligned} $$

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