Find roots of polynomial $$ p(x) = x^6+11x^4-7x^3-20x^2-7 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.1698\\[1 em]x_2 &= 1.5836\\[1 em]x_3 &= 0.0388+0.5427i\\[1 em]x_4 &= 0.0388-0.5427i\\[1 em]x_5 &= -0.2457+3.5645i\\[1 em]x_6 &= -0.2457-3.5645i \end{aligned} $$Explanation
Polynomial $ x^6+11x^4-7x^3-20x^2-7 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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