Find roots of polynomial $$ p(x) = x^2-153x+162 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 151.9337\\[1 em]x_2 &= 1.0663 \end{aligned} $$Explanation
The solutions of $ x^2-153x+162 = 0 $ are: $ x = \dfrac{ 153 }{ 2 }-\dfrac{ 9 \sqrt{ 281}}{ 2 } ~ \text{and} ~ x = \dfrac{ 153 }{ 2 }+\dfrac{ 9 \sqrt{ 281}}{ 2 }$.
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