Find roots of polynomial $$ p(x) = 196x^2+22x-11 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.1873\\[1 em]x_2 &= -0.2996 \end{aligned} $$Explanation
The solutions of $ 196x^2+22x-11 = 0 $ are: $ x = -\dfrac{ 11 }{ 196 }-\dfrac{ 3 \sqrt{ 253}}{ 196 } ~ \text{and} ~ x = -\dfrac{ 11 }{ 196 }+\dfrac{ 3 \sqrt{ 253}}{ 196 }$.
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