The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= \frac{ 5 }{ 2 }\\[1 em]x_3 &= -\frac{ 5 }{ 2 } \end{aligned} $$Step 1:
Factor out $ \color{blue}{ 4x }$ from $ 16x^3-100x $ and solve two separate equations:
$$ \begin{aligned} 16x^3-100x & = 0\\[1 em] \color{blue}{ 4x }\cdot ( 4x^2-25 ) & = 0 \\[1 em] \color{blue}{ 4x = 0} ~~ \text{or} ~~ 4x^2-25 & = 0 \end{aligned} $$One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.
Step 2:
The solutions of $ 4x^2-25 = 0 $ are: $ x = -\dfrac{ 5 }{ 2 } ~ \text{and} ~ x = \dfrac{ 5 }{ 2 }$.
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