Find roots of polynomial $$ p(x) = 16x^2+8x+1 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\frac{ 1 }{ 4 } \end{aligned} $$Explanation
The solution of $ ~ 16x^2+8x+1 = 0 ~$ is $~ x = -\dfrac{ 1 }{ 4 } ~$.
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