Find roots of polynomial $$ p(x) = 16x^2+32x+10 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.3876\\[1 em]x_2 &= -1.6124 \end{aligned} $$Explanation
The solutions of $ 16x^2+32x+10 = 0 $ are: $ x = -1-\dfrac{\sqrt{ 6 }}{ 4 } ~ \text{and} ~ x = -1+\dfrac{\sqrt{ 6 }}{ 4 }$.
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