Find roots of polynomial $$ p(x) = 15x^2+22x+11 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -\frac{ 11 }{ 15 }+\frac{ 2 \sqrt{ 11}}{ 15 }i\\[1 em]x_2 &= -\frac{ 11 }{ 15 }-2 \frac{\sqrt{ 11 }}{ 15 }i \end{aligned} $$Explanation
The solutions of $ 15x^2+22x+11 = 0 $ are: $ x = -\dfrac{ 11 }{ 15 }+\dfrac{ 2 \sqrt{ 11}}{ 15 }i ~ \text{and} ~ x = -\dfrac{ 11 }{ 15 }-\dfrac{ 2 \sqrt{ 11}}{ 15 }i$.
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