Find roots of polynomial $$ p(x) = 15x^2+112x+75 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.7437\\[1 em]x_2 &= -6.7229 \end{aligned} $$Explanation
The solutions of $ 15x^2+112x+75 = 0 $ are: $ x = -\dfrac{ 56 }{ 15 }-\dfrac{\sqrt{ 2011 }}{ 15 } ~ \text{and} ~ x = -\dfrac{ 56 }{ 15 }+\dfrac{\sqrt{ 2011 }}{ 15 }$.
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