Find roots of polynomial $$ p(x) = 15a^2+7a-3 $$
Answer
The roots of polynomial $ p(a) $ are:
$$ \begin{aligned}a_1 &= 0.2711\\[1 em]a_2 &= -0.7378 \end{aligned} $$Explanation
The solutions of $ 15a^2+7a-3 = 0 $ are: $ a = -\dfrac{ 7 }{ 30 }-\dfrac{\sqrt{ 229 }}{ 30 } ~ \text{and} ~ a = -\dfrac{ 7 }{ 30 }+\dfrac{\sqrt{ 229 }}{ 30 }$.
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