Find roots of polynomial $$ p(x) = 14x^2-53x-14 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.0336\\[1 em]x_2 &= -0.2479 \end{aligned} $$Explanation
The solutions of $ 14x^2-53x-14 = 0 $ are: $ x = \dfrac{ 53 }{ 28 }-\dfrac{\sqrt{ 3593 }}{ 28 } ~ \text{and} ~ x = \dfrac{ 53 }{ 28 }+\dfrac{\sqrt{ 3593 }}{ 28 }$.
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