Find roots of polynomial $$ p(x) = 13x^2+12x $$

The roots of polynomial $ p(x) $ are:

$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= -\frac{ 12 }{ 13 } \end{aligned} $$

Step 1:

Factor out $ \color{blue}{ x }$ from $ 13x^2+12x $ and solve two separate equations:

$$ \begin{aligned} 13x^2+12x & = 0\\[1 em] \color{blue}{ x }\cdot ( 13x+12 ) & = 0 \\[1 em] \color{blue}{ x = 0} ~~ \text{or} ~~ 13x+12 & = 0 \end{aligned} $$

One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.

Step 2:

To find the second zero, solve equation $ 13x+12 = 0 $

$$ \begin{aligned} 13x+12 & = 0 \\[1 em] 13 \cdot x & = -12 \\[1 em] x & = - \frac{ 12 }{ 13 } \end{aligned} $$

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