Find roots of polynomial $$ p(x) = 12x^2-5 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{\sqrt{ 15 }}{ 6 }\\[1 em]x_2 &= - \frac{\sqrt{ 15 }}{ 6 } \end{aligned} $$Explanation
The solutions of $ 12x^2-5 = 0 $ are: $ x = - \dfrac{\sqrt{ 15 }}{ 6 } ~ \text{and} ~ x = \dfrac{\sqrt{ 15 }}{ 6 }$.
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