Find roots of polynomial $$ p(x) = 12x^2-36x-1385 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 12.3474\\[1 em]x_2 &= -9.3474 \end{aligned} $$Explanation
The solutions of $ 12x^2-36x-1385 = 0 $ are: $ x = \dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 1059 }}{ 3 } ~ \text{and} ~ x = \dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 1059 }}{ 3 }$.
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