Find roots of polynomial $$ p(x) = 12x^2-108x-4320 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 24\\[1 em]x_2 &= -15 \end{aligned} $$Explanation
The solutions of $ 12x^2-108x-4320 = 0 $ are: $ x = -15 ~ \text{and} ~ x = 24$.
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