Find roots of polynomial $$ p(x) = 12n^2-80n+48 $$
Answer
The roots of polynomial $ p(n) $ are:
$$ \begin{aligned}n_1 &= 6\\[1 em]n_2 &= \frac{ 2 }{ 3 } \end{aligned} $$Explanation
The solutions of $ 12n^2-80n+48 = 0 $ are: $ n = \dfrac{ 2 }{ 3 } ~ \text{and} ~ n = 6$.
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