Find roots of polynomial $$ p(x) = 12a^2+24a-112 $$
Answer
The roots of polynomial $ p(a) $ are:
$$ \begin{aligned}a_1 &= 2.2146\\[1 em]a_2 &= -4.2146 \end{aligned} $$Explanation
The solutions of $ 12a^2+24a-112 = 0 $ are: $ a = -1-\dfrac{\sqrt{ 93 }}{ 3 } ~ \text{and} ~ a = -1+\dfrac{\sqrt{ 93 }}{ 3 }$.
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