Find roots of polynomial $$ p(x) = 11s^2+620s+8200 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -21.199\\[1 em]s_2 &= -35.1647 \end{aligned} $$Explanation
The solutions of $ 11s^2+620s+8200 = 0 $ are: $ s = -\dfrac{ 310 }{ 11 }-\dfrac{ 10 \sqrt{ 59}}{ 11 } ~ \text{and} ~ s = -\dfrac{ 310 }{ 11 }+\dfrac{ 10 \sqrt{ 59}}{ 11 }$.
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