Find roots of polynomial $$ p(x) = 10x^2+\frac{185}{10}x-44 $$

The roots of polynomial $ p(x) $ are:

$$ \begin{aligned}x_1 &= 1.3675\\[1 em]x_2 &= -3.2175 \end{aligned} $$

Step 1:

Get rid of fractions by multipling equation by $ \color{blue}{ 10 } $.

$$ \begin{aligned} 10x^2+\frac{185}{10}x-44 & = 0 ~~~ / \cdot \color{blue}{ 10 } \\[1 em] 100x^2+185x-440 & = 0 \end{aligned} $$

Step 2:

The solutions of $ 100x^2+185x-440 = 0 $ are: $ x = -\dfrac{ 37 }{ 40 }-\dfrac{\sqrt{ 8409 }}{ 40 } ~ \text{and} ~ x = -\dfrac{ 37 }{ 40 }+\dfrac{\sqrt{ 8409 }}{ 40 }$.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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