Find roots of polynomial $$ p(x) = 10x^2+120x+1000 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -6+8i\\[1 em]x_2 &= -6-8i \end{aligned} $$Explanation
The solutions of $ 10x^2+120x+1000 = 0 $ are: $ x = -6+8i ~ \text{and} ~ x = -6-8i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator