Find roots of polynomial $$ p(x) = 10x^2-3x-75 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.8927\\[1 em]x_2 &= -2.5927 \end{aligned} $$Explanation
The solutions of $ 10x^2-3x-75 = 0 $ are: $ x = \dfrac{ 3 }{ 20 }-\dfrac{\sqrt{ 3009 }}{ 20 } ~ \text{and} ~ x = \dfrac{ 3 }{ 20 }+\dfrac{\sqrt{ 3009 }}{ 20 }$.
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