Find roots of polynomial $$ p(x) = \frac{1021}{10}x^2+\frac{1021}{10}x-\frac{304}{10} $$

The roots of polynomial $ p(x) $ are:

$$ \begin{aligned}x_1 &= 0.2401\\[1 em]x_2 &= -1.2401 \end{aligned} $$

Step 1:

Get rid of fractions by multipling equation by $ \color{blue}{ 10 } $.

$$ \begin{aligned} \frac{1021}{10}x^2+\frac{1021}{10}x-\frac{304}{10} & = 0 ~~~ / \cdot \color{blue}{ 10 } \\[1 em] 1021x^2+1021x-304 & = 0 \end{aligned} $$

Step 2:

The solutions of $ 1021x^2+1021x-304 = 0 $ are: $ x = -\dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 2283977 }}{ 2042 } ~ \text{and} ~ x = -\dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 2283977 }}{ 2042 }$.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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