Find roots of polynomial $$ p(x) = 1000x^2-44x-1000 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.0222\\[1 em]x_2 &= -0.9782 \end{aligned} $$Explanation
The solutions of $ 1000x^2-44x-1000 = 0 $ are: $ x = \dfrac{ 11 }{ 500 }-\dfrac{\sqrt{ 250121 }}{ 500 } ~ \text{and} ~ x = \dfrac{ 11 }{ 500 }+\dfrac{\sqrt{ 250121 }}{ 500 }$.
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