Find roots of polynomial $$ p(x) = 1000x^2-12500x+9850 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 11.6549\\[1 em]x_2 &= 0.8451 \end{aligned} $$Explanation
The solutions of $ 1000x^2-12500x+9850 = 0 $ are: $ x = \dfrac{ 25 }{ 4 }-\dfrac{\sqrt{ 11685 }}{ 20 } ~ \text{and} ~ x = \dfrac{ 25 }{ 4 }+\dfrac{\sqrt{ 11685 }}{ 20 }$.
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