Find roots of polynomial $$ p(x) = 10-3x^2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{\sqrt{ 30 }}{ 3 }\\[1 em]x_2 &= - \frac{\sqrt{ 30 }}{ 3 } \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} 10-3x^2 & = 0\\[1 em] -3x^2+10 & = 0 \end{aligned} $$Step 2:
The solutions of $ -3x^2+10 = 0 $ are: $ x = - \dfrac{\sqrt{ 30 }}{ 3 } ~ \text{and} ~ x = \dfrac{\sqrt{ 30 }}{ 3 }$.
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