The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1\\[1 em]x_2 &= -6 \end{aligned} $$Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 6 } $.
$$ \begin{aligned} 1-\frac{5}{6}x-\frac{1}{6}x^2 & = 0 ~~~ / \cdot \color{blue}{ 6 } \\[1 em] 6-5x-x^2 & = 0 \end{aligned} $$Step 2:
Write polynomial in descending order
$$ \begin{aligned} 6-5x-x^2 & = 0\\[1 em] -x^2-5x+6 & = 0 \end{aligned} $$Step 3:
The solutions of $ -x^2-5x+6 = 0 $ are: $ x = -6 ~ \text{and} ~ x = 1$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.