Find roots of polynomial $$ p(x) = 1-4x^2-3x+18 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.8365\\[1 em]x_2 &= -2.5865 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ \color{blue}{1} -4x^2-3x+ \color{blue}{18} = -4x^2-3x+ \color{blue}{19} $$Step 2:
The solutions of $ -4x^2-3x+19 = 0 $ are: $ x = -\dfrac{ 3 }{ 8 }-\dfrac{\sqrt{ 313 }}{ 8 } ~ \text{and} ~ x = -\dfrac{ 3 }{ 8 }+\dfrac{\sqrt{ 313 }}{ 8 }$.
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