Find roots of polynomial $$ p(x) = -x^6-x^5+x^4+x^3+x^2-x+2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.2401\\[1 em]x_2 &= -1.7032\\[1 em]x_3 &= 0.4328+0.6988i\\[1 em]x_4 &= 0.4328-0.6988i\\[1 em]x_5 &= -0.7012+0.954i\\[1 em]x_6 &= -0.7012-0.954i \end{aligned} $$Explanation
Polynomial $ -x^6-x^5+x^4+x^3+x^2-x+2 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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