Find roots of polynomial $$ p(x) = -x^4-13x^2+48 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.7321\\[1 em]x_2 &= -1.7321\\[1 em]x_3 &= 4i\\[1 em]x_4 &= -4i \end{aligned} $$Explanation
Polynomial $ -x^4-13x^2+48 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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