Find roots of polynomial $p (x) = - x^{3} + x^{2} + 14 x - 18$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} = 1.3268 = 3.5235 = - 3.8503$

Explanation

Polynomial $- x^{3} + x^{2} + 14 x - 18$ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.

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Find roots of polynomial p(x)=−x3+x2+14x−18

The roots of polynomial p(x) are: x1​x2​x3​​=1.3268=3.5235=−3.8503​

Find roots of polynomial $p (x) = - x^{3} + x^{2} + 14 x - 18$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} = 1.3268 = 3.5235 = - 3.8503$