Find roots of polynomial $$ p(x) = -x^2+8x+10 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 9.099\\[1 em]x_2 &= -1.099 \end{aligned} $$Explanation
The solutions of $ -x^2+8x+10 = 0 $ are: $ x = 4-\sqrt{ 26 } ~ \text{and} ~ x = 4+\sqrt{ 26 }$.
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