Find roots of polynomial $$ p(x) = -x^2+4x-3-4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2+\sqrt{ 3 }i\\[1 em]x_2 &= 2-\sqrt{ 3 }i \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ -x^2+4x \color{blue}{-3} \color{blue}{-4} = -x^2+4x \color{blue}{-7} $$Step 2:
The solutions of $ -x^2+4x-7 = 0 $ are: $ x = 2+\sqrt{ 3 }i ~ \text{and} ~ x = 2-\sqrt{ 3 }i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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