Find roots of polynomial $$ p(x) = -x^2+30x-20 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 29.3178\\[1 em]x_2 &= 0.6822 \end{aligned} $$Explanation
The solutions of $ -x^2+30x-20 = 0 $ are: $ x = 15-\sqrt{ 205 } ~ \text{and} ~ x = 15+\sqrt{ 205 }$.
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