Find roots of polynomial $$ p(x) = -x^2+30x-100 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 26.1803\\[1 em]x_2 &= 3.8197 \end{aligned} $$Explanation
The solutions of $ -x^2+30x-100 = 0 $ are: $ x = 15-5 \sqrt{ 5 } ~ \text{and} ~ x = 15+5 \sqrt{ 5 }$.
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