Find roots of polynomial $$ p(x) = -x^2+10x-3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 9.6904\\[1 em]x_2 &= 0.3096 \end{aligned} $$Explanation
The solutions of $ -x^2+10x-3 = 0 $ are: $ x = 5-\sqrt{ 22 } ~ \text{and} ~ x = 5+\sqrt{ 22 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator