Find roots of polynomial $$ p(x) = -x^2-8x+60 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.7178\\[1 em]x_2 &= -12.7178 \end{aligned} $$Explanation
The solutions of $ -x^2-8x+60 = 0 $ are: $ x = -4-2 \sqrt{ 19 } ~ \text{and} ~ x = -4+2 \sqrt{ 19 }$.
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