Find roots of polynomial $$ p(x) = -x^2-8x-17 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -4+i\\[1 em]x_2 &= -4-i \end{aligned} $$Explanation
The solutions of $ -x^2-8x-17 = 0 $ are: $ x = -4+i ~ \text{and} ~ x = -4-i$.
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