Find roots of polynomial $$ p(x) = -x^2-7x+8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1\\[1 em]x_2 &= -8 \end{aligned} $$Explanation
The solutions of $ -x^2-7x+8 = 0 $ are: $ x = -8 ~ \text{and} ~ x = 1$.
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