Find roots of polynomial $$ p(x) = -x^2-7-4x $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -2+\sqrt{ 3 }i\\[1 em]x_2 &= -2-\sqrt{ 3 }i \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} -x^2-7-4x & = 0\\[1 em] -x^2-4x-7 & = 0 \end{aligned} $$Step 2:
The solutions of $ -x^2-4x-7 = 0 $ are: $ x = -2+\sqrt{ 3 }i ~ \text{and} ~ x = -2-\sqrt{ 3 }i$.
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