Find roots of polynomial $$ p(x) = -x^2-6x-10 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -3+i\\[1 em]x_2 &= -3-i \end{aligned} $$Explanation
The solutions of $ -x^2-6x-10 = 0 $ are: $ x = -3+i ~ \text{and} ~ x = -3-i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator