Find roots of polynomial $$ p(x) = -x^2-20x-39 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -2.1898\\[1 em]x_2 &= -17.8102 \end{aligned} $$Explanation
The solutions of $ -x^2-20x-39 = 0 $ are: $ x = -10-\sqrt{ 61 } ~ \text{and} ~ x = -10+\sqrt{ 61 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator