Find roots of polynomial $$ p(x) = -6x^2-x+40 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 5 }{ 2 }\\[1 em]x_2 &= -\frac{ 8 }{ 3 } \end{aligned} $$Explanation
The solutions of $ -6x^2-x+40 = 0 $ are: $ x = -\dfrac{ 8 }{ 3 } ~ \text{and} ~ x = \dfrac{ 5 }{ 2 }$.
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