Find roots of polynomial $$ p(x) = -6x^2-32x+560 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 7.3555\\[1 em]x_2 &= -12.6889 \end{aligned} $$Explanation
The solutions of $ -6x^2-32x+560 = 0 $ are: $ x = -\dfrac{ 8 }{ 3 }-\dfrac{ 2 \sqrt{ 226}}{ 3 } ~ \text{and} ~ x = -\dfrac{ 8 }{ 3 }+\dfrac{ 2 \sqrt{ 226}}{ 3 }$.
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