Find roots of polynomial $$ p(x) = -6x^2-276+1998 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \sqrt{ 287 }\\[1 em]x_2 &= -\sqrt{ 287 } \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ -6x^2 \color{blue}{-276} + \color{blue}{1998} = -6x^2+ \color{blue}{1722} $$Step 2:
The solutions of $ -6x^2+1722 = 0 $ are: $ x = -\sqrt{ 287 } ~ \text{and} ~ x = \sqrt{ 287 }$.
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